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If `G` is universal gravitational constant and `g` is acceleration due to gravity, then the unit of the quantity `G/g`
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Mar 19, 2022
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If `G` is universal gravitational constant and `g` is acceleration due to gravity, then the unit of the quantity `G/g` is
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(a) `kg-m^2` (b) `kgm^(-1)` (c) `kgm^(-2)` (d) `m^2 kg^(-1)`
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Acceleration due to gravityThe acceleration for any object moving under the sole influence of gravity is known as acceleration due to gravity. So, for an object of mass `m,` the acceleration experienced by it is usually denoted by the symbol g which is related to F by Newton’s second law by relation `F= mg`. Thus,`g=F/m=(GM_e)/(r_e^2)`Acceleration `g` is readily measurable as `R_e` is a known quantity. The measurement of `G` by Cavendish’s experiment (or otherwise), combined with knowledge of `g and R_e` enables one to estimate `M_e` from the above equation. This is the reason why there is a popular statement