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If a current I given by `I_O sin(omegat-pi/ 2)` flows in an ac circuit across which an ac potential of `E = E_O sinomegat` has been applied, then the power consumption p in the circuit will be,
Options:
(a) `P=(E_oI_o)/(sqrt2)` (b) `P=sqrt2E_oI_o` (c) `P=(E_oI_o)/2` (d) `P = 0`

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