Proton in an Electric Field
Potential difference `(DeltaV)` between two points `A and B` separated by a distance `x`, in a uniform electric field `E` is given by `DeltaV =-Ex`, where `x` is measured parallel to the field lines. If a charge `q_0` moves from A to B, the change in potential energy `(DeltaU)` is given as `DeltaU=q_0 DeltaV`. A proton is released from rest in uniform electric field of magnitude `8.0 xx 10^4 Vm^(-1)` directed along the positive X-axis. The proton undergoes a displacement of 0.50 m in the direction of E.
Mass of a proton `= 1.66 xx 10^(-27) kg` and charge on a proton `=1.6 xx 10^(-19) C`.
The change in electric potential energy of the proton for displacement from A to B is
Options:
(a) `-6.4 xx 10^(-19) J`
(b) `6.4 xx 10^(-19) J`
(c) `-6.4 xx 10^(-15) J`
(d) `6.4 xx 10^(-15) J`