Proton in an Electric Field
Potential difference `(DeltaV)` between two points `A and B` separated by a distance `x`, in a uniform electric field `E` is given by `DeltaV =-Ex`, where `x` is measured parallel to the field lines. If a charge `q_0` moves from A to B, the change in potential energy `(DeltaU)` is given as `DeltaU=q_0 DeltaV`. A proton is released from rest in uniform electric field of magnitude `8.0 xx 10^4 Vm^(-1)` directed along the positive X-axis. The proton undergoes a displacement of 0.50 m in the direction of E.
Mass of a proton `= 1.66 xx 10^(-27) kg` and charge on a proton `=1.6 xx 10^(-19) C`.
The velocity `(v_B)` of the proton after it has moved `0.50 m` starting from rest is
Options:
(a) `1.6 xx 10^8 ms^(-1)`
(b) `2.77 xx 10^6 ms^(-1)`
(c) `2.77 xx 10^4 ms^(-1)`
(d) `1.6 xx 10^6 ms^(-1)`