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Pure inductance of 3H each are connected as shown below. The equivalent inductance of the circuit
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Mar 20, 2022
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12th Physics
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varun
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A coil of inductance 300 mH and resistance `2Omega` is connected to a source of voltage 2V. The current reaches half of its steady state value
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If rotational velocity of a dynamo armature is doubled, then induced emf will become...What is increased in step down transformer
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The core of a transformer is laminated so
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In transformer, core is made of soft iron to
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An ideal transformer has 1:25 turn ratio. The peak value of the ac is 28 V. The rms ms secondary voltage is nearest
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A primary winding of transformer has 500 turns whereas its secondary has 5000 turns. Primary is connected to ac supply of 20V, 50Hz The secondary output
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A step down transformer is connected to main supply 200 V to operate a 6V, 30 w bulb. The current in primary
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An emf of 15 V is applied in a circuit containing 5H inductance & `10 Omega` resistance. The ratio of the currents at time `t=oo` and at t =
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Two coils have a mutual inductance 0.005H The current changes in a coil according to equation `I = I_O sinomegat` Where `I_O = 10 A & ω= 100 π rad s^(-1)` The maximum value of emf in second coil
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A coil of inductance 8.4 mH and resistance `6Omega` is connected to a 12 V battery. The current in the coil is 1A in the
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Alternating current can not be measured by dc ammeter
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The resistance of a coil for dc is in ohms. In ac, the
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An alternating current of rms valuve 10 A is passed through a `12_Omega` resistance. The maximum potential difference across the resistor
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220 V,50 Hz, ac is applied to a resistor. The instantancous value of voltage
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The rms value of an ac of 50 Hz is 10 amp.The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will
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If a current I given by `I_O sin(omegat-pi/ 2)` flows in an ac circuit across which an ac potential of `E = E_O sinomegat` has been applied, then the power consumption p in the circuit will
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In general in an alternating current
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An alternating current is given by the `eq^n` I = I1 coswt + I2 sinwb. The rms current is given
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In an ac circuit, the current is given by `I= 5sin[ 100 t -pi/2]` and the ac potential is `V = 200 sin 100t`. Then the power consumption
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