Login

Remember

Register

All Activity
Q&A
Questions
Hot!
Unanswered
Tags
Categories
Users
Ask a Question

Consider the relation for relative velocities between two objects A and B, `v_(BA) = v_(AB)` The above equation is valid,

0 votes

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

Consider the relation for relative velocities between two objects A and B,
`v_(BA) = v_(AB)` The above equation is valid, if

Options:
(a) `v_A and v_B` are average velocities (b) `v_A and v_B` are instantaneous velocities
(c) `v_A and v_B` are average speed (d) Both( a) and ( b)

marks1
chapter3
#mcq

Please log in or register to answer this question.

0 Answers

Categories

All categories
Maths (8.6k)
Science (14)
Physics (3.4k)
- 11th Physics (1.5k)
- 12th Physics (1.9k)

Related questions

Assertion If we consider system of two bodies `A and B` as a whole, `F_(AB) and F_(BA)` are internal forces of the system `(A + B)`. They add to give a null force. Reason: Internal forces in a body or a system of particles cancel away in
(a) Define the term relative velocity?(b) Write the expression for relative velocity of one moving with respect to another body when objects are moving in same direction and are moving in opposite directions?(c) A Jet airplane traveling at the speed of 500km/hr ejects its products of combustion at the speed of 1500km/h relative to the Jet plane. What is the speed of the latter with respect to an observer on the
Acceleration due to gravityThe acceleration for any object moving under the sole influence of gravity is known as acceleration due to gravity. So, for an object of mass `m,` the acceleration experienced by it is usually denoted by the symbol g which is related to F by Newton’s second law by relation `F= mg`. Thus,`g=F/m=(GM_e)/(r_e^2)`Acceleration `g` is readily measurable as `R_e` is a known quantity. The measurement of `G` by Cavendish’s experiment (or otherwise), combined with knowledge of `g and R_e` enables one to estimate `M_e` from the above equation. This is the reason why there is a popular statement
Acceleration due to gravityThe acceleration for any object moving under the sole influence of gravity is known as acceleration due to gravity. So, for an object of mass `m,` the acceleration experienced by it is usually denoted by the symbol g which is related to F by Newton’s second law by relation `F= mg`. Thus,`g=F/m=(GM_e)/(r_e^2)`Acceleration `g` is readily measurable as `R_e` is a known quantity. The measurement of `G` by Cavendish’s experiment (or otherwise), combined with knowledge of `g and R_e` enables one to estimate `M_e` from the above equation. This is the reason why there is a popular statement
Acceleration due to gravityThe acceleration for any object moving under the sole influence of gravity is known as acceleration due to gravity. So, for an object of mass `m,` the acceleration experienced by it is usually denoted by the symbol g which is related to F by Newton’s second law by relation `F= mg`. Thus,`g=F/m=(GM_e)/(r_e^2)`Acceleration `g` is readily measurable as `R_e` is a known quantity. The measurement of `G` by Cavendish’s experiment (or otherwise), combined with knowledge of `g and R_e` enables one to estimate `M_e` from the above equation. This is the reason why there is a popular statement

Send feedback