A projectile is given an initial velocity of `(hati + 2hatj) ms^(-1)`, where `hati` is along the ground and `hatj` is along vertical. If `g` is `10 ms^(-2)`, then the equation of its trajectory is
Options:
(a) `y = x - 5x^2`
(b) `y = 2x-5x^2`
(c) `4y = 2x - 5x^2`
(d) `4y= 2x-25x^2`