State Graham’s law of diffusion and derive

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asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

State Graham’s law of diffusion and derive it?

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From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 `cm^3` `s^(–1)`. The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 `cm^3` `s^(–1)`. Identify the gas. [Hint : Use Graham’s law of diffusion: R1/R2 = ( M2 /M1 )1/2, where R1, R2 are diffusion rates of gases 1 and 2, and M1 and M2 their respective molecular masses. The law is a simple consequence of kinetic
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A gas in equilibrium has uniform density and pressure throughout its volume. This is strictly true only if there are no external influences. A gas column under gravity, for example, does not have uniform density (and pressure). As you might expect, its density decreases with height. The precise dependence is given by the so-called law of atmospheres ` n^2` = `n^1` exp [ -mg (`h_2` – `h_1`)/ kB T] where` n-2`, `n-1` refer to number density at heights `h_2` and `h_1` respectively. Use this relation to derive the equation for sedimentation equilibrium of a suspension in a liquid column: `n_2`