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`(–4)^(–4) xx (4)^(–1) =
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Jan 17, 2022
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uday
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`(–4)^(–4) xx (4)^(–1) = (4)^5`
marks1
chapter8
#tnf
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`24.58 = 2 xx 10 + 4 xx 1 + 5 xx 10 + 8 xx
`(–4)^(–4) xx (4)^(–1) =
`24.58 = 2 xx 10 + 4 xx 1 + 5 xx 10 + 8 xx
`(–4)^(–4) xx (4)^(–1) =
`24.58 = 2 xx 10 + 4 xx 1 + 5 xx 10 + 8 xx