The emf across `AB` at `t=l/(2v)` is
A conducting square wire frame ABCD of side `l` is pulled by horizontal force so that it moves with constant velocity v. A uniform magnetic field of strength B is existing perpendicular to the plane of wire. The resistance per unit length of wire is `lambda` and negligible self inductance. If at `t= 0,` frame is just at the boundary of magnetic field. Then
Options:
(a) `(Bvl)/4`
(b) zero
(c) `Bvl`
(d) None of these