0 votes
in 12th Physics by (6.7k points)
The potential energy of a charged parallel plate capacitor is `U_0`. If a slab of dielectric constant `K` is inserted between the plates, then new potential energy will be
Options:
(a) `(U_0)/K` (b) `U_0K^2` (c) `(U_0)/(K^2)` (d) `U_0^2`

Please log in or register to answer this question.

Categories