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Two identical capacitors, have the same capacitance C. One of them is charged to potential `V_1` and the other to `V_2`. Likely charged plates are then connected. Then the decrease in energy of the combined system is
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(a) `1/4C(V_1^2-V_2^2)` (b) `1/4C(V_1^2+V_2^2)` (c) `1/4C(V_1-V_2)` (d) `1/4C(V_1+V_2)`

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