Login
Remember
Register
Home
All Activity
Q&A
Questions
Hot!
Unanswered
Tags
Categories
Users
Ask a Question
Ask a Question
Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum
0
votes
asked
Mar 20, 2022
in
12th Physics
by
varun
(
6.7k
points)
Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).
marks3
chapter11
#sub
Please
log in
or
register
to answer this question.
0
Answers
Categories
All categories
Maths
(8.6k)
Science
(14)
Physics
(3.4k)
11th Physics
(1.5k)
12th Physics
(1.9k)
Related questions
What is the de Broglie wavelength of a nitrogen molecule in air at 300 K? Assume that the molecule is moving with the root-meansquare speed of molecules at this temperature. (Atomic mass of nitrogen = 14.0076
An electromagnetic wave of wavelength λ is incident on a photosensitive surface of negligible work function. If the photoelectrons emitted form this surface have de-broglie wavelength `λ_1` . Prove that
A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813 × 10–4. Calculate the particle’s mass and identify the
Compute the typical de Broglie wavelength of an electron in a metal at 27 °C and compare it with the mean separation between two electrons in a metal which is given to be about 2 × 10–10 m. [Note: Exercises 35 and 36 reveal that while the wave-packets associated with gaseous molecules under ordinary conditions are non-overlapping, the electron wave-packets in a metal strongly overlap with one another. This suggests that whereas molecules in an ordinary gas can be distinguished apart, electrons in a metal cannot be distintguished apart from one another. This indistinguishibility has many fundamental implications which you
What is the(a) momentum, (b) speed, (c) de Broglie wavelength of an electron with kinetic energy of 120