Questions by vaibhav

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On dividing `p/3` by `3/p`, the quotient is

asked Jan 17, 2022 in 8th-maths

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Subtract : `5a^2b^2c^2` from `–

asked Jan 17, 2022 in 8th-maths

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Simplyfy `(1.5p + 1.2q)^2 – (1.5p –

asked Jan 17, 2022 in 8th-maths

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Expand the following, using suitable identities. `(a^2 +

asked Jan 17, 2022 in 8th-maths

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Write the greatest common factor in each of the following terms. `– 18a^2,

asked Jan 17, 2022 in 8th-maths

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Factorise the following expressions. `ax^3 – bx^2 +

asked Jan 17, 2022 in 8th-maths

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Factorise the following expressions. `63p^2q^2r^2s – 9pq^2r^2s^2 + 15p^2qr^2s^2 –

asked Jan 17, 2022 in 8th-maths

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Factorise the following expressions. `24x^2yz^3 – 6xy^3z^2 + 15x^2y^2z –

asked Jan 17, 2022 in 8th-maths

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Factorise the following expressions. `lx + my + mx +

asked Jan 17, 2022 in 8th-maths

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Factorise the following expressions. `2x^2 – 2y + 4xy –

asked Jan 17, 2022 in 8th-maths

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Factorise the following expressions. `y^2 + 8zx – 2xy –

asked Jan 17, 2022 in 8th-maths

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Factorise the following, using the identity `a^2 + 2ab + b^2 = (a + b)^2` `x^2 + 14x +

asked Jan 17, 2022 in 8th-maths

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Factorise the following, using the identity `a^2 + 2ab + b^2 = (a + b)^2` `4x^2 + 4x +

asked Jan 17, 2022 in 8th-maths

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Factorise the following, using the identity `a^2 + 2ab + b^2 = (a + b)^2` `a^2x^2 + 2abx +

asked Jan 17, 2022 in 8th-maths

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Factorise the following, using the identity `a^2 – 2ab + b^2 = (a – b)^2`. `p^2 – 2p +

asked Jan 17, 2022 in 8th-maths

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Factorise the following, using the identity `a^2 – 2ab + b^2 = (a – b)^2`. `a^2y^3 – 2aby^2 +

asked Jan 17, 2022 in 8th-maths

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Factorise the following. `18 + 11x +

asked Jan 17, 2022 in 8th-maths

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Factorise the following. `x^2 – 10x +

asked Jan 17, 2022 in 8th-maths

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Factorise the following using the identity `a^2 – b^2 = (a + b) (a – b)`.

asked Jan 17, 2022 in 8th-maths

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Factorise the following using the identity `a^2 – b^2 = (a + b) (a – b)`. `y^4 –

asked Jan 17, 2022 in 8th-maths

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