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Match the Column I (quantities) with Column II (approximate values) and select the correct answer from the codes given below. Column I Column II A. Escape velocity of earth p. `1.6 m'/'s^2` B. Gravitational acceleration at moon’s surface q. `6400 km` C. Radius of earth r. `11.2 km'/'s`
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A satellite of mass m revolving with a velocity v around the earth. With reference to the above situation, match the Column I (types of energy) with Column II (expression) and select the correct answer from the codes given below. Column I Column II A. Kinetic energy of the satellite p. `-1/2mv^2` B. Potential energy of the satellite q. `1/2mv^2` C. Total energy of the satellite r. `-mv^2`
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Assertion: Newton’s law of universal gravitation states that a particle attracts every other particle in the universe using a force of attraction that is directly proportional to the product of their masses and inversely proportional to the square of distance between them.Reason: Law of gravitation is analogous to magnetic force between the moving
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Assertion: The value of acceleration due to gravity does not depend upon mass of the body on which force is applied. Reason: Acceleration due to gravity is a variable
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Assertion: As we go up the surface of the earth, we feel light weighed than on the surface of the earth. Reason: The acceleration due to gravity decreases on going up above the surface of the
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Assertion: Work done by or against gravitational force in moving a body from one point to another is independent of the actual path followed between the two points. Reason: This is because gravitational forces are conservative in
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Mar 19, 2022
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Assertion: If gravitational potential at some point is positive, then the gravitational field strength at that point will also be zero. Reason: Except at infinity gravitational potential due to a system of point masses at some finite distance cannot be
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Assertion: The force of attraction between a hollow spherical shell of uniform density and a point mass situated inside it, is zero. Reason: The value of G does not depend on the nature and size of the
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Assertion: Moon has no atmosphere. Reason: The escape speed for the moon is much
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Assertion: The escape velocity for a planet is `v_e=sqrt(2gR)`. If the radius of the planet is four times, the escape velocity becomes half `(i.e. v_e'=(v_e)/2)`.Reason: In the relation for escape velocity, `v_e =sqrt(2gR)`, the acceleration due to gravity `g` is inversely proportional to radius of the planet. Thus, `v_e prop
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Assertion: The velocity of the satellite increases as its height above earth’s surface increases and is minimum near the surface of the earth. Reason: The velocity of the satellite is directly proportional to square root of its height above earth’s
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Assertion: A satellite moves around the earth in a circular orbit under the action of gravity. A person in the satellite experience zero gravity field in the satellite. Reason: The contact force by the surface on the person is not
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Assertion: The total energy of the satellite is always negative irrespective of the nature of its orbit, i.e. elliptical or circular and it cannot be positive or zero. Reason: If the total energy is negative the satellite would leave its
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Assertion: The geo-stationary satellite goes around the earth in west-east direction. Reason Geo-stationary satellites orbits around the earth in the equatorial plane with `T=24 h` same as that of the rotation of the earth around its
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Assertion: In the satellite, everything inside it is in a state of free fall. Reason: Every part and parcel of the satellite has zero
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Assertion: An object is weightless when it is in free fall and this phenomenon is called weightlessness. Reason: In free fall, there is upward force acting on the
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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.The big spheres attract the nearby small ones by a force which
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marks1
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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.The net force on the bar
asked
Mar 19, 2022
in
11th Physics
by
varun
(
6.7k
points)
marks1
chapter8
#mcq
0
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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.The net torque on the bar
asked
Mar 19, 2022
in
11th Physics
by
varun
(
6.7k
points)
marks1
chapter8
#mcq
0
votes
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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.The torque produces twist in the suspended wire. The twisting stops
asked
Mar 19, 2022
in
11th Physics
by
varun
(
6.7k
points)
marks1
chapter8
#mcq
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