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Conservation of Momentum This principle is a consequence of Newton’s second and third laws of motion.In an isolated system (i.e. a system having no external force), mutual forces (called internal forces) between pairs of particles in the system causes momentum change in individual particles.Let a bomb be at rest, then its momentum will be zero. If the bomb explodes into two equal parts, then the parts fly off in exactly opposite directions with same speed, so that the total momentum is still zero. Here, no external force is applied on the system of particles (bomb).A bullet of mass 0.1 kg
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Mar 19, 2022
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varun
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Conservation of Momentum This principle is a consequence of Newton’s second and third laws of motion.In an isolated system (i.e. a system having no external force), mutual forces (called internal forces) between pairs of particles in the system causes momentum change in individual particles.Let a bomb be at rest, then its momentum will be zero. If the bomb explodes into two equal parts, then the parts fly off in exactly opposite directions with same speed, so that the total momentum is still zero. Here, no external force is applied on the system of particles (bomb).A unidirectional force F varying with
asked
Mar 19, 2022
in
11th Physics
by
varun
(
6.7k
points)
marks1
chapter5
#mcq
0
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0
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Conservation of Momentum This principle is a consequence of Newton’s second and third laws of motion.In an isolated system (i.e. a system having no external force), mutual forces (called internal forces) between pairs of particles in the system causes momentum change in individual particles.Let a bomb be at rest, then its momentum will be zero. If the bomb explodes into two equal parts, then the parts fly off in exactly opposite directions with same speed, so that the total momentum is still zero. Here, no external force is applied on the system of particles (bomb).Two masses of `M and 4M`
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Mar 19, 2022
in
11th Physics
by
varun
(
6.7k
points)
marks1
chapter5
#mcq
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Force of Friction on Connected Bodies When bodies are in contact, there are mutual contact forces satisfying the third law of motion. The component of contact force normal to the surfaces in contact is called normal reaction. The component parallel to the surfaces in contact is called friction.In the above figure, `8 kg and 6 kg` are hanging stationary from a rough pulley and are about to move. They are stationary due to roughness of the pulley.Which force is acting between pulley and
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Mar 19, 2022
in
11th Physics
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varun
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6.7k
points)
marks1
chapter5
#mcq
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Force of Friction on Connected Bodies When bodies are in contact, there are mutual contact forces satisfying the third law of motion. The component of contact force normal to the surfaces in contact is called normal reaction. The component parallel to the surfaces in contact is called friction.In the above figure, `8 kg and 6 kg` are hanging stationary from a rough pulley and are about to move. They are stationary due to roughness of the pulley.The normal reaction acting on the system
asked
Mar 19, 2022
in
11th Physics
by
varun
(
6.7k
points)
marks1
chapter5
#mcq
0
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0
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Force of Friction on Connected Bodies When bodies are in contact, there are mutual contact forces satisfying the third law of motion. The component of contact force normal to the surfaces in contact is called normal reaction. The component parallel to the surfaces in contact is called friction.In the above figure, `8 kg and 6 kg` are hanging stationary from a rough pulley and are about to move. They are stationary due to roughness of the pulley.The tension is more on side having mass
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Mar 19, 2022
in
11th Physics
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varun
(
6.7k
points)
marks1
chapter5
#mcq
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Force of Friction on Connected Bodies When bodies are in contact, there are mutual contact forces satisfying the third law of motion. The component of contact force normal to the surfaces in contact is called normal reaction. The component parallel to the surfaces in contact is called friction.In the above figure, `8 kg and 6 kg` are hanging stationary from a rough pulley and are about to move. They are stationary due to roughness of the pulley.The force of friction acting on the rope
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Mar 19, 2022
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11th Physics
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varun
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6.7k
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marks1
chapter5
#mcq
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Force of Friction on Connected Bodies When bodies are in contact, there are mutual contact forces satisfying the third law of motion. The component of contact force normal to the surfaces in contact is called normal reaction. The component parallel to the surfaces in contact is called friction.In the above figure, `8 kg and 6 kg` are hanging stationary from a rough pulley and are about to move. They are stationary due to roughness of the pulley.Coefficient of friction of the pulley
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Force of `50 N` acting on a body at an angle `theta` with horizontal. If `150 J` work is done by displacing it `3 m,` then `theta`
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A particle is pushed by forces `2hati + 3hatj -2 hatk and 5hati -hatj - 3hatk` simultaneously and it is displaced from point `hati + hatj + hatk` to point `2hati - hatj + 3hatk`. The work done
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Consider a force `F=- xhati + yhatj` The work done by this force in moving a particle from point `A(1, 0)` to `B(0,1)` along the line segment is (all quantities are in SI
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A body moves from point A to B under the action of a force varying in magnitude as shown in figure, then the work done is (force is expressed in newton and displacement in
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A string of length `L` and force constant `k` is stretched to obtain extension `l`. It is further stretched to obtain extension `l_1`,. The work done in second stretching
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A uniform chain of length `l` and mass `m` is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If `g` is acceleration due to gravity, work required to pull the hanging part on to the table
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If `W_1, W_2 and W_3` are the work done in moving a particle from A and B along three different paths 1, 2 and 3 respectively (as shown) in the gravitational field of a point mass `m`, the relation between `W_1, W_2 and W_3`
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Amongst the given graphs which one correctly represents the variation of the kinetic energy `(K)` of a body with velocity
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The kinetic energy of a body of mass `4 kg` and momentum `6 N-s` will
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For a moving particle (mass `m`, velocity `v`) having a momentum `p`, which one of the following correctly describes the kinetic energy of the
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Two bodies of masses `4 kg and 5 kg` are moving with equal momentum. Then, the ratio of their respective kinetic energies
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A heavy body and a light body have same kinetic energy. Which will have larger linear
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