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The expression for `8^(–2)` as a power with the base 2 is
asked Jan 17, 2022 in 8th-maths by Arun (1.7k points)
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By multiplying `(10)^5` by `(10)^(–10)` we get
asked Jan 17, 2022 in 8th-maths by Simran (1.8k points)
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`[(2/13)^(-1) -: (2/13)^3]^3 xx (2/13)^(-13)` =
asked Jan 17, 2022 in 8th-maths by nishit (1.8k points)
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Find the value `[4^(–1) +3^(–1) +
asked Jan 17, 2022 in 8th-maths by purvi (1.8k points)
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`[2^(–1) + 3^(–1) + 4^(–1)]^0` =
asked Jan 17, 2022 in 8th-maths by purvi (1.8k points)
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The standard form of `(1/100000000)` is
asked Jan 17, 2022 in 8th-maths by sumit (1.6k points)
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The standard form of 12340000 is
asked Jan 17, 2022 in 8th-maths by vaibhav (1.7k points)
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The usual form of `3.41 xx 10^6` is
asked Jan 17, 2022 in 8th-maths by nikhil (1.8k points)
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The usual form of `2.39461 xx 10^6` is
asked Jan 17, 2022 in 8th-maths by purvi (1.8k points)
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By multiplying `(5/3)^4` by ________ we get
asked Jan 17, 2022 in 8th-maths by yogita (1.8k points)
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`3^5 -: 3^–6` can be simplified as
asked Jan 17, 2022 in 8th-maths by vaibhav (1.7k points)
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The value of `3 xx 10^(-7)` is equal to
asked Jan 17, 2022 in 8th-maths by Arun (1.7k points)
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The standard form for 32,50,00,00,000 is
asked Jan 17, 2022 in 8th-maths by uday (1.6k points)
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The standard form for 0.000000008 is
asked Jan 17, 2022 in 8th-maths by purvi (1.8k points)
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The usual form for `2.3 xx 10^(-10)` is
asked Jan 17, 2022 in 8th-maths by krutika (1.7k points)
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On dividing `8^5` by _________ we get
asked Jan 17, 2022 in 8th-maths by Arun (1.7k points)
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