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Assertion: As we go up the surface of the earth, we feel light weighed than on the surface of the earth. Reason: The acceleration due to gravity decreases on going up above the surface of the

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: Work done by or against gravitational force in moving a body from one point to another is independent of the actual path followed between the two points. Reason: This is because gravitational forces are conservative in

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: If gravitational potential at some point is positive, then the gravitational field strength at that point will also be zero. Reason: Except at infinity gravitational potential due to a system of point masses at some finite distance cannot be

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: The force of attraction between a hollow spherical shell of uniform density and a point mass situated inside it, is zero. Reason: The value of G does not depend on the nature and size of the

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: Moon has no atmosphere. Reason: The escape speed for the moon is much

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Assertion: The escape velocity for a planet is `v_e=sqrt(2gR)`. If the radius of the planet is four times, the escape velocity becomes half `(i.e. v_e'=(v_e)/2)`.Reason: In the relation for escape velocity, `v_e =sqrt(2gR)`, the acceleration due to gravity `g` is inversely proportional to radius of the planet. Thus, `v_e prop

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: The velocity of the satellite increases as its height above earth’s surface increases and is minimum near the surface of the earth. Reason: The velocity of the satellite is directly proportional to square root of its height above earth’s

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: A satellite moves around the earth in a circular orbit under the action of gravity. A person in the satellite experience zero gravity field in the satellite. Reason: The contact force by the surface on the person is not

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: The total energy of the satellite is always negative irrespective of the nature of its orbit, i.e. elliptical or circular and it cannot be positive or zero. Reason: If the total energy is negative the satellite would leave its

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: The geo-stationary satellite goes around the earth in west-east direction. Reason Geo-stationary satellites orbits around the earth in the equatorial plane with `T=24 h` same as that of the rotation of the earth around its

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: In the satellite, everything inside it is in a state of free fall. Reason: Every part and parcel of the satellite has zero

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Assertion: An object is weightless when it is in free fall and this phenomenon is called weightlessness. Reason: In free fall, there is upward force acting on the

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.The big spheres attract the nearby small ones by a force which

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.The net force on the bar

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.The net torque on the bar

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.The torque produces twist in the suspended wire. The twisting stops

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Cavendish’s ExperimentThe figure shows the schematic drawing of Cavendish’s experiment to determine the value of the gravitational constant. The bar AB has two small lead spheres attached at its ends. The bar is suspended from a rigid support by a fine wire.Two large lead spheres are brought close to the small ones but on opposite sides as shown. The value of G from this experiment came to be `6.67 xx 10^(-11) N-m^2'/'kg^2`.After Cavendish’s experiment, there have been given suggestions that the value of the gravitational constant G becomes smaller when considered over very large time period (in billions of years)

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Acceleration due to gravityThe acceleration for any object moving under the sole influence of gravity is known as acceleration due to gravity. So, for an object of mass `m,` the acceleration experienced by it is usually denoted by the symbol g which is related to F by Newton’s second law by relation `F= mg`. Thus,`g=F/m=(GM_e)/(r_e^2)`Acceleration `g` is readily measurable as `R_e` is a known quantity. The measurement of `G` by Cavendish’s experiment (or otherwise), combined with knowledge of `g and R_e` enables one to estimate `M_e` from the above equation. This is the reason why there is a popular statement

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Acceleration due to gravityThe acceleration for any object moving under the sole influence of gravity is known as acceleration due to gravity. So, for an object of mass `m,` the acceleration experienced by it is usually denoted by the symbol g which is related to F by Newton’s second law by relation `F= mg`. Thus,`g=F/m=(GM_e)/(r_e^2)`Acceleration `g` is readily measurable as `R_e` is a known quantity. The measurement of `G` by Cavendish’s experiment (or otherwise), combined with knowledge of `g and R_e` enables one to estimate `M_e` from the above equation. This is the reason why there is a popular statement

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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Acceleration due to gravityThe acceleration for any object moving under the sole influence of gravity is known as acceleration due to gravity. So, for an object of mass `m,` the acceleration experienced by it is usually denoted by the symbol g which is related to F by Newton’s second law by relation `F= mg`. Thus,`g=F/m=(GM_e)/(r_e^2)`Acceleration `g` is readily measurable as `R_e` is a known quantity. The measurement of `G` by Cavendish’s experiment (or otherwise), combined with knowledge of `g and R_e` enables one to estimate `M_e` from the above equation. This is the reason why there is a popular statement

asked Mar 19, 2022 in 11th Physics by varun (6.7k points)

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