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The value of `[2^(–1) xx 3^(–1)]^(–1)` is

asked Jan 17, 2022 in 8th-maths by Simran (1.8k points)

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The multiplicative inverse of `(– 4)^(–2) is

asked Jan 17, 2022 in 8th-maths by uday (1.6k points)

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The multiplicative inverse of `(3/2)^2` is not equal to

asked Jan 17, 2022 in 8th-maths by Arun (1.7k points)

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`24.58 = 2 xx 10 + 4 xx 1 + 5 xx 10 + 8 xx

asked Jan 17, 2022 in 8th-maths by nikhil (1.8k points)

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`(–5)^(–2) xx (–5)^(–3) =

asked Jan 17, 2022 in 8th-maths by Simran (1.8k points)

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`5^0 =

asked Jan 17, 2022 in 8th-maths by purvi (1.8k points)

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`(–2)^0 =

asked Jan 17, 2022 in 8th-maths by vaibhav (1.7k points)

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`(–6)^0 =

asked Jan 17, 2022 in 8th-maths by sumit (1.6k points)

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`(–7)^(–4) xx (–7)^2 =

asked Jan 17, 2022 in 8th-maths by purvi (1.8k points)

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The value of `(1/4)^(-2)` is equal to

asked Jan 17, 2022 in 8th-maths by nikhil (1.8k points)

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The standard form for 203000 is `2.03 xx

asked Jan 17, 2022 in 8th-maths by Arun (1.7k points)

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The value of `5^(–2)` is equal to

asked Jan 17, 2022 in 8th-maths by Arun (1.7k points)

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Express `27/64` and `(-27)/64` as powers of a rational

asked Jan 17, 2022 in 8th-maths by vaibhav (1.7k points)

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A half-life is the amount of time that it takes for a radioactive substance to decay to one half of its original quantity. Suppose radioactive decay causes 300 grams of a substance to decrease to `300 xx 2^(–3)` grams after 3 half-lives. Evaluate `300 xx 2^(–3)` to determine how many grams of the substance are left. Explain why the expression `300 xx 2^(–n)` can be used to find the amount of the substance that remains after n

asked Jan 17, 2022 in 8th-maths by sumit (1.6k points)

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Use the properties of exponents to verify that each statement is true. (a) `1/4(2^n) = 2^(n-2)` (b) `4(n-1) = 1/4(4)^n` (c) `25(5^(n–2)) =

asked Jan 17, 2022 in 8th-maths by nishit (1.8k points)

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Simplify: `(1/2)^2-(1/4)^(3-1) =

asked Jan 17, 2022 in 8th-maths by nikhil (1.8k points)

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Rs 1600 lent at a compound interest of 5% per annum, compounded half yearly for one year will amount

asked Jan 17, 2022 in 8th-maths by krutika (1.7k points)

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Ashima took a loan of Rs 1,00,000 at 12% p.a. compounded half yearly. She paid Rs 1,12,360. If (1.06)2 is equal to 1.1236, then the period for which she took the loan

asked Jan 17, 2022 in 8th-maths by nishit (1.8k points)

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For calculation of interest compounded half yearly, keeping the principal same, which one of the following is

asked Jan 17, 2022 in 8th-maths by Arun (1.7k points)

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The compound interest on Rs 8,000 for one year at 16% p.a. compounded half yearly is _________, given that `(1.08)^2 =

asked Jan 17, 2022 in 8th-maths by purvi (1.8k points)

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