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Write the greatest common factor in each of the following terms. `qrxy, pryz,
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Jan 18, 2022
in
8th-maths
by
yogita
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1.8k
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marks2
chapter9
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Write the greatest common factor in each of the following terms. `11x^2,
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Jan 18, 2022
in
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nikhil
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marks2
chapter9
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Factorise the following expressions. `a^2b + a^2c + ab + ac + b^2c +
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Jan 18, 2022
in
8th-maths
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Simran
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1.8k
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marks3
chapter9
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Factorise the following, using the identity `a^2 + 2ab + b^2 = (a + b)^2` `a^2x^2 + 2ax +
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Jan 18, 2022
in
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yogita
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1.8k
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marks3
chapter9
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Factorise the following, using the identity `a^2 – 2ab + b^2 = (a – b)^2`. `x^2 – 8x +
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Jan 18, 2022
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8th-maths
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yogita
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1.8k
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marks3
chapter9
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Factorise the following, using the identity `a^2 – 2ab + b^2 = (a – b)^2`. `4a^2 – 4ab +
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Jan 18, 2022
in
8th-maths
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nikhil
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1.8k
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marks3
chapter9
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Factorise the following, using the identity `a^2 – 2ab + b^2 = (a – b)^2`. `p^2y^2 – 2py +
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Jan 18, 2022
in
8th-maths
by
nishit
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1.8k
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marks3
chapter9
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Factorise the following. `18 + 11x +
asked
Jan 18, 2022
in
8th-maths
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yogita
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1.8k
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marks3
chapter9
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Factorise the following. `y^2 + 7y +
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Jan 18, 2022
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sumit
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marks3
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Factorise the following. `p^2 – 13p –
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Jan 18, 2022
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nikhil
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marks3
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Factorise the following using the identity `a^2 – b^2 = (a + b) (a – b)`. `3a^2b^3 –
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Jan 18, 2022
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8th-maths
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marks3
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Factorise the following using the identity `a^2 – b^2 = (a + b) (a – b)`.
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Jan 18, 2022
in
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yogita
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1.8k
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marks3
chapter9
#sub
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Factorise the following using the identity `a^2 – b^2 = (a + b) (a – b)`. `y^4 –
asked
Jan 18, 2022
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8th-maths
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nikhil
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1.8k
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marks3
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Factorise the expressions and divide them as directed: `(x^3 + x^2 – 132x) -: x (x –
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Jan 18, 2022
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vaibhav
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marks3
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Factorise the expressions and divide them as directed: `(3x^4 – 1875) -: (3x^2 –
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Jan 18, 2022
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8th-maths
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krutika
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1.7k
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marks3
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Verify the following: `(a + b + c) (a^2 + b^2 + c^2 – ab – bc – ca) = a^3 + b^3+ c^3 –
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Jan 18, 2022
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marks3
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Simplify
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Jan 18, 2022
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purvi
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marks1
chapter8
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In `2^n`, n is known
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Jan 18, 2022
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1.7k
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marks1
chapter8
#mcq
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The value of `3^5 -: 3^(–6)`
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Jan 18, 2022
in
8th-maths
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purvi
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1.8k
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marks1
chapter8
#mcq
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The value of `(–2)^(2xx3–1)`
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Jan 18, 2022
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marks1
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