A 60 HP electric motor lifts an elevator having a maximum total load capacity of `2000 kg`. If the frictional force on the elevator is `4000 N`, the speed of the elevator at full load is close to (take, `1 HP = 746 W and g=10 ms^(-2)`)
Options:
(a) `2.0 ms^(-1)`
(b) `1.5 ms^(-1)`
(c) `1.9 ms^(-1)`
(d) `1.7 ms^(-1)`