Login
Remember
Register
Home
All Activity
Q&A
Questions
Hot!
Unanswered
Tags
Categories
Users
Ask a Question
Ask a Question
The acceleration due to gravity on the surface of moon is 1.7 m/`s^2`. What is the time period of simple pendulum on moon if its time period on the earth is
0
votes
asked
Mar 19, 2022
in
11th Physics
by
varun
(
6.7k
points)
The acceleration due to gravity on the surface of moon is 1.7 m/`s^2`. What is the time period of simple pendulum on moon if its time period on the earth is 3.5s?
marks2
chapter14
#sub
Please
log in
or
register
to answer this question.
0
Answers
Categories
All categories
Maths
(8.6k)
Science
(14)
Physics
(3.4k)
11th Physics
(1.5k)
12th Physics
(1.9k)
Related questions
The acceleration due to gravity on the surface of moon is 1.7 m `s^(–2)`. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m
Consider a simple pendulum, having a bob attached to a string, that oscillates under the action of the force of gravity. Suppose that the period of oscillation of the simple pendulum depends on its length (l), mass of the bob (m) and acceleration due to gravity (g). Derive the expression for its time period using method of
A simple pendulum of length l and having a bob of mass M is suspended in a car. The car is moving on a circular track of radius R with a uniform speed v. If the pendulum makes small oscillations in a radial direction about its equilibrium position, what will be its time period
Given that T stands for time period and `l` stands for the length of simple pendulum. If g is the acceleration due to gravity, then which of the following statements about the relation `T^2= l'/'g` is
Answer the following questions : (a) Time period of a particle in SHM depends on the force constant k and mass m of the particle: `T=2πsqrt(m/k)`. A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum? (b) The motion of a simple pendulum is approximately simple harmonic for small angle oscillations. For larger angles of oscillation, a more involved analysis shows that T is greater than `2πsqrt(l/g)`.Think of a qualitative argument to appreciate this result. (c) A man with a wristwatch on his hand falls from the top