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The acceleration due to gravity on the surface of moon is 1.7 m `s^(–2)`. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m
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The acceleration due to gravity on the surface of moon is 1.7 m `s^(–2)`. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m `s^(–2)`)
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