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Refer to the arrangement of charges in Fig. and a Gaussian surface of radius R with Q at the centre.

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asked Mar 20, 2022 in 12th Physics by varun (6.7k points)

Refer to the arrangement of charges in Fig. and a Gaussian surface of radius R with Q at the centre. Then

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(a) total flux through the surface of the sphere is ` –Q/ ε_0` .
(b) field on the surface of the sphere re is `Q/(4piepsilon_0R^2`
(c) flux through the surface of sphere due to 5Q is zero.
(d) field on the surface of sphere due to –2Q is same everywhere.

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