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A parallel plate capacitor is charged by a battery which is then disconnected. A dielectric slab is then inserted to fill the space between the plates. Match the changes that could occur with Column II.
Column I Column II
A. Charge on the capacitor plates p. Decrease by a factor of K
B. Intensity of electric field q. Increase by a factor of K
C. Energy stored r. Remains same
D. Capacitance s. None
Options:
(a) `A-r B-p C-s D-q` (b) `A-r B-p C-p D-q` (c) `A-r B_s C-p D-q` (d) `A-p B-p C-q D-s`

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