0 votes
in 12th Physics by (6.7k points)
Electron Moving in Magnetic Field An electron with a speed `v_0 ( < < c)` moves in a circle of radius `r_0`, in a uniform magnetic field. This electron is able to travel in a circular path as magnetic field is perpendicular to the velocity of the electron. The time required for one revolution of the electron is `T_0`. The speed of the electron is now, doubled to `2v_0`.

A charged particle is projected in a magnetic field `B=(2hati + 4 hatj) xx 10^2 T`. The acceleration of the particle is found to be `a=(xhati + 2hatj)ms^(-2)`. Find the value of `x`.
Options:
(a) 4 (b) `-4` (c) `-2` (d) `2`

Please log in or register to answer this question.

Categories