A proton moves with a speed of `7.45×10^5 m'/'s` directly towards a free proton originally at rest. Find the distance of closest approach for the two protons.
Given : `1/(4pi epsilon_0)= 9×10^9 (N-m)^2/c^2 ; m_p=1.67×10^(–27) kg and e = 1.6×10^(–19) C`