Ask a Question

A physical quantity P is related to four observables a, b, c and d as follows : `P=(a^3b^2)/(sqrtcd)` The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2%, respectively. What is the percentage error in the quantity P ?If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result

0 votes
in 11th Physics by (6.7k points)
A physical quantity P is related to four observables a, b, c and d as follows : `P=(a^3b^2)/(sqrtcd)` The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2%, respectively. What is the percentage error in the quantity P ?If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ?

Please log in or register to answer this question.